With this new constraint (which I will call interlocking
horizontal neighbors), I will offer 2 answers to be debated. The
first is 120, since now the rows are all 10 "dots" wide and
they just shift back and forth, forming triangles. However, this
leaves approx 250 feet wasted at the top of the square (since there is
no longer a benefit to "squaring up" the sides. So, I
will throw out another, softer number of 125 which is the average for
two squares stacked vertically (the 250 feet from each add up to
enough to make another row which takes 457 feet, and they split the
number in the row).
Tim
Team AZFastFeet
Okay, maybe I
opened a can of worms here...
I should be more
specific...I was trying to figure out how many caches can fit into a
square mile, leaving enough buffer zone (.05 mile) around the
edges, so each square mile around the area in question can also
have the same amount of caches?
Any math geniuses
out there? Anyone?
Scott and I were
discussing this today, and also called it a "Power
Grid"...
Maybe on
Terracaching.com....thinking, thinking.....